Question

В однородном электрическом поле переместили заряд 20 мккл в направлении силовой линии на расстояниие 50см разность потенциалов между начальной и конечной точками равна 220 в.найти напряженность поля и работу электрического поля по перемещению заряда

Answer 1

Решение в скане...........

Answer 2

Calculation of Electric Field Intensity and Work Done by Electric Field

To find the electric field intensity and work done by the electric field, we can use the formula:

Electric field intensity (E) = Voltage (V) / Distance (d)

Given: - Charge (q) = 20 μC - Distance (d) = 50 cm = 0.5 m - Voltage (V) = 220 V

Using the formula, we can calculate the electric field intensity:

Electric field intensity (E) = 220 V / 0.5 m

Calculating the value:

Electric field intensity (E) = 440 V/m

Now, let's calculate the work done by the electric field:

Work done (W) = Charge (q) * Voltage (V)

Calculating the value:

Work done (W) = 20 μC * 220 V

Converting the charge to coulombs:

Work done (W) = 20 * 10^-6 C * 220 V

Calculating the value:

Work done (W) = 4.4 * 10^-3 J

Therefore, the electric field intensity is 440 V/m and the work done by the electric field is 4.4 * 10^-3 J.

Please note that the calculations provided are based on the given information and may not take into account other factors that could affect the results.