Question

Масса солнца больше массы земли в 333000 раз, а радиус в 109 раз. Зная ускорение свободного падения на поверхности, определить ускорение свободного падения на поверхности солнца

Answer 1

Радиус солнца = 695 500 км.
масса солнца = 1 988 920 000 000 000 000 000 000 000 000 кг.
радиус в квадрате =  483 720 250 000 км.

28 x m \ R^2 = 273.1  

Ответ: 273.1 м \ с^2                                               формула - g = G x m \ R^2

Answer 2

Calculating Acceleration Due to Gravity on the Surface of the Sun

The mass of the Sun is 333,000 times greater than the mass of the Earth, while the radius of the Sun is 109 times greater than the radius of the Earth. Given this information, we can calculate the acceleration due to gravity on the surface of the Sun.

The formula to calculate the acceleration due to gravity is:

g = G * (M / R^2)

Where: - g = acceleration due to gravity - G = gravitational constant - M = mass of the celestial body - R = radius of the celestial body

Using the values provided: - Mass of the Sun (M) = 333,000 * mass of the Earth - Radius of the Sun (R) = 109 * radius of the Earth

We can calculate the acceleration due to gravity on the surface of the Sun using the above formula.

Calculation

Given: - Mass of the Earth (m) = 5.972 × 10^24 kg - Radius of the Earth (r) = 6.371 × 10^6 m - Gravitational constant (G) = 6.67430 × 10^-11 m^3 kg^-1 s^-2

Using the formula: g = G * (M / R^2)

Substituting the values: g = (6.67430 × 10^-11) * (333,000 * 5.972 × 10^24) / (109^2 * 6.371 × 10^6)

Calculating the value of g will give us the acceleration due to gravity on the surface of the Sun.

Result

The calculated acceleration due to gravity on the surface of the Sun is approximately 274 m/s^2.

This high value is due to the Sun's enormous mass and relatively small radius compared to the Earth.