Question

Камень брошен вертикально вверх с начальной скоростью 25 м/c. Определите модуль скорости камня через 1.5 с после начала движения

Answer 1

vo=25    t=1.5   g=10    v=?

v=vo - g*t=25 - 10*1.5=10 м/с

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Answer 2

Problem Analysis

We are given that a stone is thrown vertically upwards with an initial velocity of 25 m/s. We need to determine the magnitude of the stone's velocity after 1.5 seconds.

Solution

To solve this problem, we can use the equations of motion for uniformly accelerated motion. In this case, the stone is thrown vertically upwards, so the acceleration due to gravity will act in the opposite direction to the motion of the stone.

The equation that relates the final velocity (v), initial velocity (u), acceleration (a), and time (t) is:

v = u + at (Equation 1)

In this case, the stone is thrown upwards, so the acceleration due to gravity (a) will be negative (-9.8 m/s^2). The initial velocity (u) is 25 m/s, and the time (t) is 1.5 seconds.

Substituting these values into Equation 1, we can calculate the final velocity (v):

v = 25 m/s + (-9.8 m/s^2) * 1.5 s

Now, let's calculate the final velocity.

Calculation

Using the given values in Equation 1, we can calculate the final velocity (v):

v = 25 m/s + (-9.8 m/s^2) * 1.5 s

Simplifying the equation:

v = 25 m/s - 14.7 m/s

v = 10.3 m/s

Therefore, the magnitude of the stone's velocity after 1.5 seconds is 10.3 m/s.

Answer

The magnitude of the stone's velocity after 1.5 seconds is 10.3 m/s.