Question

Какова сила,действующая со стороны воды на ворота шлюза шириной 12 м ,если глубина воды в шлюзе 8 м?

Answer 1

H= 8 мL=12 мƥ=1000кг/m3g=10 Н/кг-------------------------давление на поверхности  po=0 Падавление на дне  p=ƥgh = 1000*10*8=80000 Пасреднее давление p(cp)= (p-po)/2 = 80000 Па / 2 =40000 Паплощадь ворот S = h*Lсила  F=p(cp)*S = 40000*8*12=3 840 000 Н = 3.84  МНОТВЕТ 3 840 000 Н = 3.84  МН  - мегаНьютон

Answer 2

Calculating the Force Exerted by Water on the Lock Gates

To calculate the force exerted by water on the lock gates, we can use the formula:

Force = Pressure × Area

Where: - Pressure is the pressure exerted by the water at a certain depth. - Area is the area of the gate being acted upon by the water.

Calculating Pressure Exerted by Water

The pressure exerted by water at a certain depth can be calculated using the formula:

Pressure = Density × Gravity × Depth

Where: - Density of water is approximately 1000 kg/m^3. - Gravity is approximately 9.81 m/s^2. - Depth is the depth of the water.

Given that the depth of the water in the lock is 8 m, we can calculate the pressure exerted by the water.

Pressure = 1000 kg/m^3 × 9.81 m/s^2 × 8 m

Calculating the Area of the Gate

The area of the gate being acted upon by the water can be calculated using the formula:

Area = Width × Height

Given that the width of the gate is 12 m, and assuming the height of the gate is equal to the depth of the water (8 m), we can calculate the area of the gate.

Area = 12 m × 8 m

Final Calculation

Now, we can calculate the force exerted by the water on the lock gates using the previously mentioned formulas.

Force = Pressure × Area

Substitute the calculated values for pressure and area into the formula to find the force.

Force = (1000 kg/m^3 × 9.81 m/s^2 × 8 m) × (12 m × 8 m)

Force = 78480 N/m^2 × 96 m^2

Force = 7,540,800 N

Therefore, the force exerted by the water on the lock gates with a width of 12 m and a depth of 8 m is approximately 7,540,800 Newtons.