Question

Конденсатор включен в сеть переменного тока стандартной частоты. Напряжение в сети 220 В. Сила тока в цепи конденсатора 2.5 А. Какова емкость конденсатора? Заранее спасибо за помощь!

Answer 1

Xc=220/2.5=88 реактивный ом 
Хс=1/(omega*C) 
C=1(omega*Xc)=1(2*3.14*50гц*88)=3,619e-5=36,19мкФ

Answer 2

Calculation of Capacitance

To calculate the capacitance of the capacitor in the given circuit, we can use the formula:

C = I / (2πfV)

Where: - C is the capacitance in farads (F) - I is the current in amperes (A) - f is the frequency in hertz (Hz) - V is the voltage in volts (V)

In this case, the current in the circuit is 2.5 A, the frequency is the standard frequency of the alternating current (which is typically 50 Hz), and the voltage is 220 V.

Plugging in these values into the formula, we get:

C = 2.5 A / (2π * 50 Hz * 220 V)

Now let's calculate the value of the capacitance using the given values.

C = 2.5 A / (2π * 50 Hz * 220 V) = 2.5 / (2 * 3.1416 * 50 * 220) F

Calculating this expression gives us the value of the capacitance.