Question

Сколько капель образуется из 1 см3 воды, если она капает из трубки диаметром 1,8 мм? Коэффициент поверхностного натяжения воды 0,073 Н/м

Answer 1

Считаем плотность воды равной 1гр/мл, значит масса воды равна 1 грамм.
Сила поверхностного натяжения равна весу одной капли.
F = mg
F = σS; S = πd ⇒ F = σ×πd ⇒ mg = σπd⇒ масса одной капли равна
m = σ×πd/g = (0,073x3,14x1,8x10⁻³)/10 = 4,126·10⁻⁶ кг.
Число капель равно 1·10⁻³/4,126·10⁻⁶ = 0,24·10³ = 240 капель.

Answer 2

Calculating the Number of Drops

To calculate the number of drops formed from 1 cm^3 of water when it drips from a tube with a diameter of 1.8 mm, we can use the formula:

Number of drops = Volume of water / Volume of one drop

The volume of one drop can be calculated using the formula for the volume of a sphere: V = (4/3) * π * r^3, where r is the radius of the drop.

Volume of One Drop

The radius of the drop can be calculated using the diameter of the tube, which is 1.8 mm. The radius (r) is half of the diameter, so r = 0.9 mm = 0.09 cm.

Now, we can calculate the volume of one drop: V = (4/3) * π * (0.09 cm)^3

Surface Tension Coefficient

The surface tension coefficient of water is given as 0.073 N/m.

Calculation

Now, we can use the given information to calculate the number of drops formed from 1 cm^3 of water.

Number of drops = 1 cm^3 / Volume of one drop

Let's calculate the volume of one drop and then use it to find the number of drops.