Question

какое количество теплоты выделится при конденсации водяного пара,взятого при температуре 100 градусов цельсия ,если масса пара равна 2 кг?

Answer 1

Q=Lm (L пара =22.6 *10^{-5} Дж/кг) =22.6 * 10^{-5} * 2=45.2 ** 10^{-5} Дж. 

Answer 2

Calculation of Heat Released during Condensation of Water Vapor

To calculate the amount of heat released during the condensation of water vapor, we can use the formula:

Q = m * L

Where: - Q is the heat released (in joules) - m is the mass of the water vapor (in kilograms) - L is the latent heat of vaporization of water (in joules per kilogram)

Given that the mass of the water vapor is 2 kg and the temperature is 100 degrees Celsius, we can calculate the heat released.

First, we need to find the latent heat of vaporization of water at 100 degrees Celsius. Let's refer to the search results for this information.

According to the latent heat of vaporization of water is 23 * 10^5 joules per kilogram.

Now, we can substitute the values into the formula:

Q = 2 kg * (23 * 10^5 J/kg) = 46 * 10^5 J = 4.6 * 10^6 J

Therefore, the amount of heat released during the condensation of 2 kg of water vapor at 100 degrees Celsius is 4.6 * 10^6 joules.