Question

Определить энергию, массу и импульс фотона с длиной волны 240 нм.

Answer 1

Энергия E=hс/λмасса    m=E/c^2импульс р=h/λλ=250 нм.с=3*10^8 м/сh =6.626*10^-34 Дж*с

Answer 2

Determining the Energy, Mass, and Momentum of a Photon with a Wavelength of 240 nm

To determine the energy, mass, and momentum of a photon with a wavelength of 240 nm, we can use the following formulas:

1. Energy of a photon (E): - The energy of a photon can be calculated using the equation: E = hc/λ, where h is Planck's constant (6.626 x 10^-34 J·s), c is the speed of light (3 x 10^8 m/s), and λ is the wavelength of the photon. - Plugging in the values, we get: E = (6.626 x 10^-34 J·s) x (3 x 10^8 m/s) / (240 x 10^-9 m). - Calculating this, we find that the energy of the photon is approximately 8.72 x 10^-19 J.

2. Mass of a photon (m): - Photons are massless particles, according to the theory of relativity. Therefore, the mass of a photon is zero.

3. Momentum of a photon (p): - The momentum of a photon can be calculated using the equation: p = E/c, where E is the energy of the photon and c is the speed of light. - Plugging in the values, we get: p = (8.72 x 10^-19 J) / (3 x 10^8 m/s). - Calculating this, we find that the momentum of the photon is approximately 2.91 x 10^-27 kg·m/s.

Therefore, for a photon with a wavelength of 240 nm, the energy is approximately 8.72 x 10^-19 J, the mass is zero, and the momentum is approximately 2.91 x 10^-27 kg·m/s.