Question

Собачья упряжка начинает тащить стоящие на снегу сани массой 100 кг с постоянной силой 149 Н За какой промежуток времени сани проедут первые 200 м пути? Коэффициент трения скольжения полозьев о снег 0,05

Answer 1

a=(F-Ft)/m;
Ft=km*g;
a=(149-0,05*100*9,8)/100= 1;
t=((2*S)/a)^0,5;
t=((400/1)^0,5=20(c)

Answer 2

Calculation of Time Taken for Sleds to Travel the First 200m

To calculate the time taken for the sleds to travel the first 200m, we need to consider the force of friction and the mass of the sleds.

Given: - Mass of the sleds (m) = 100 kg - Force applied (F) = 149 N - Coefficient of sliding friction (μ) = 0.05 - Distance traveled (d) = 200 m

The force of friction (Ff) can be calculated using the equation:

Ff = μ * m * g

Where: - μ is the coefficient of sliding friction - m is the mass of the sleds - g is the acceleration due to gravity (approximately 9.8 m/s^2)

Substituting the given values:

Ff = 0.05 * 100 kg * 9.8 m/s^2

Calculating the force of friction:

Ff = 49 N

The net force acting on the sleds (Fnet) can be calculated using the equation:

Fnet = F - Ff

Substituting the given values:

Fnet = 149 N - 49 N

Calculating the net force:

Fnet = 100 N

The acceleration of the sleds (a) can be calculated using the equation:

Fnet = m * a

Substituting the given values:

100 N = 100 kg * a

Calculating the acceleration:

a = 1 m/s^2

To calculate the time taken (t) for the sleds to travel the first 200m, we can use the equation:

d = 0.5 * a * t^2

Rearranging the equation to solve for t:

t = sqrt(2 * d / a)

Substituting the given values:

t = sqrt(2 * 200 m / 1 m/s^2)

Calculating the time taken:

t ≈ 20 s

Therefore, it will take approximately 20 seconds for the sleds to travel the first 200 meters.