Question

Энергия электрического поля конденсатора электроемкостью 10 микрофарад при напряжении 20 Ватт

Answer 1

Напряжение в Вольт (В)
мощность в Ваттах (Вт)

Answer 2

C=10мкФ
U=20 В
W-?

$W= \frac{C U^{2} }{2} = \frac{ 10*10^{-9 } * 10^{2}}{2} = \frac{ 10^{-8}*10^{2} }{2} = \frac{ 10^{-6} }{2}=5* 10^{-7}$ Дж

Answer 3

Electric Field Energy in a Capacitor

The energy stored in an electric field of a capacitor can be calculated using the formula:

U = (1/2) * C * V^2

Where: - U is the energy stored in the electric field - C is the capacitance of the capacitor - V is the voltage across the capacitor

In this case, the electric field energy of a capacitor with a capacitance of 10 microfarads and a voltage of 20 volts can be calculated using the given values in the formula.

Using the formula, the energy stored in the electric field of the capacitor can be calculated as:

U = (1/2) * 10 * 10^-6 * (20)^2

Calculating this value gives:

U = 1 * 10^-6 * 400

U = 0.0004 Joules

Therefore, the energy stored in the electric field of the capacitor is 0.0004 Joules.