Question

Выпуклый мост имеет форму круга радиусом 125м. Автомобиль массой 2 т движется по мосту со скоростью 72 км / ч. С какой силой автомобиль давит на поверхность дороги в момент прохождения середины моста? Считайте g = 10 м / с2.

Answer 1

R=125 м              сила давления автомобиля в средней точке моста
m=2 т =2000 кг        равна его весу в этой точке:
v=72 км/ч=20 м/с            Fд=P=m(g-a)=m(g-v²/R);
g=10 м/с²                         Fд=2000(10-400/125)=
_____________                   =2000(10-3,2)=2000*6,8=13600 Н;
Fд-?                         Ответ: Fд=13600 Н.

Answer 2

Calculation of the Force

To calculate the force with which the car presses on the surface of the road when passing through the middle of the bridge, we can use the centripetal force formula:

F = (m * v^2) / r

Where: - F is the force - m is the mass of the car (2 tons = 2000 kg) - v is the velocity of the car (72 km/h = 20 m/s) - r is the radius of the bridge (125 m)

Let's substitute the given values into the formula and calculate the force:

F = (2000 kg * (20 m/s)^2) / 125 m

Calculating this expression, we find that the force exerted by the car on the surface of the road when passing through the middle of the bridge is approximately 6400 N.

Please note that the above calculation assumes that the car is moving in a circular path along the bridge and neglects other forces such as friction and air resistance.