Question

Два одинаковых шарика с зарядами 1.8*10^-7 Кл и 8.0*10^-7 Кл приведены в соприкосновение и вновь раздвинуты на расстояние 0.5 м . Определите силу взаимодействия между ними

Answer 1

Fкул=(k*q*q)/r*r  q=(q1+q2)/2

Answer 2

Calculating the Force of Interaction between Two Charged Spheres

When two identical spheres with charges of 1.8*10^-7 C and 8.0*10^-7 C are brought into contact and then separated by a distance of 0.5 m, we can calculate the force of interaction between them using the following steps:

1. Calculate the Charge on Each Sphere After Contact: - When the two spheres are brought into contact, they will share charge and each will have the same charge. - The final charge on each sphere after contact can be calculated using the principle of conservation of charge.

2. Calculate the Force of Interaction: - Once the charges on the spheres are determined, we can use Coulomb's law to calculate the force of interaction between them.

Calculation Steps

1. Calculate the Charge on Each Sphere After Contact: - According to the principle of conservation of charge, the total charge is conserved. Therefore, the final charge on each sphere after contact can be calculated as the average of the initial charges.

- The final charge on each sphere after contact: - \( Q_f = \frac{Q_1 + Q_2}{2} \) - Where \( Q_1 = 1.8*10^-7 C \) and \( Q_2 = 8.0*10^-7 C \)

- Substituting the values: - \( Q_f = \frac{1.8*10^-7 + 8.0*10^-7}{2} \) - \( Q_f = \frac{9.8*10^-7}{2} \) - \( Q_f = 4.9*10^-7 C \)

- Therefore, the final charge on each sphere after contact is \( 4.9*10^-7 C \).

2. Calculate the Force of Interaction: - Now that we have the final charge on each sphere, we can use Coulomb's law to calculate the force of interaction between them.

- Coulomb's law states that the force of interaction between two point charges is given by: - \( F = \frac{k * |Q_1 * Q_2|}{r^2} \) - Where: - \( F \) = force of interaction - \( k \) = Coulomb's constant (\( 8.9875*10^9 N m^2/C^2 \)) - \( Q_1 \) and \( Q_2 \) = charges on the spheres - \( r \) = distance between the centers of the spheres

- Substituting the values: - \( F = \frac{8.9875*10^9 * |4.9*10^-7 * 4.9*10^-7|}{(0.5)^2} \) - \( F = \frac{8.9875*10^9 * 2.401*10^-13}{0.25} \) - \( F = \frac{2.155*10^-3}{0.25} \) - \( F ≈ 8.62*10^-3 N \)

Conclusion

The force of interaction between the two spheres with charges of 1.8*10^-7 C and 8.0*10^-7 C, when separated by a distance of 0.5 m, is approximately 8.62*10^-3 N.