Question

Автомобиль массой 3 т трогается с места и двигается по горизонтальной дороге с ускорением 2 м/с^2. Определить работу совершенную двигателем авто на пути 500 м. Коэффициент трения 0,05

Answer 1

Дано:
m=3000кг
a=2m/c^2
S=500м
M(мю)(коэффициентр трения)=0,05
g=10m/c^2
найти:A-?
решение:
A=F*S
Рисуем рисунок, получается:
OX:F-Fтр=ma:Fтр=MN; F-MN=ma
OY:N-mg=0
N=mg⇒F-Mmg=ma; F=m(a+Mg)
A=m(a+Mg)*S
A=3000(2+0,05*10)*500=8000Дж.

Answer 2

Calculation of Work Done by the Engine

To calculate the work done by the engine of a car, we need to consider the force applied by the engine and the distance traveled by the car. In this case, the car has a mass of 3 tons (3000 kg) and accelerates with an acceleration of 2 m/s^2 on a horizontal road. The coefficient of friction is given as 0.05, but it is not clear how it relates to the problem. Therefore, we will assume that the coefficient of friction is not relevant to the calculation of work done by the engine.

The work done by the engine can be calculated using the formula:

Work = Force x Distance

To find the force applied by the engine, we can use Newton's second law of motion:

Force = Mass x Acceleration

Given: - Mass of the car (m) = 3000 kg - Acceleration (a) = 2 m/s^2 - Distance traveled (d) = 500 m

Using the formula for force, we can calculate the force applied by the engine:

Force = Mass x Acceleration Force = 3000 kg x 2 m/s^2 Force = 6000 N Now, we can calculate the work done by the engine using the formula:

Work = Force x Distance Work = 6000 N x 500 m Work = 3,000,000 Nm or 3,000,000 J

Therefore, the work done by the engine of the car on a 500 m path is 3,000,000 Joules (J).

Please note that the coefficient of friction was not considered in this calculation as it was not clear how it relates to the problem. If you have any additional information or clarification regarding the coefficient of friction, please let me know and I will be happy to assist you further.