Question

Какое кол-во теплоты выделится при кристаллизации 1 кг свинца , взятого при температуре 327 градусов Цельсия и дальнейшем охлаждении до 17 градусов Цельсия?

Answer 1

Q=c*m*t1-t2
где c=130 Дж/кг*C
m=1кг
разница t= 327-17=310 C
Q= 130*1*310=40300 Дж=40,3 кДж

Answer 2

Calculation of Heat Released during Crystallization of Lead

To calculate the amount of heat released during the crystallization of 1 kg of lead, we need to use the formula:

Q = m * C * (T2 - T1)

Where: - Q is the heat released (in joules) - m is the mass of the substance (in kg) - C is the specific heat capacity of the substance (in J/kg°C) - T2 is the final temperature (in °C) - T1 is the initial temperature (in °C)

In this case, we have: - m = 1 kg (mass of lead) - T2 = 17°C (final temperature) - T1 = 327°C (initial temperature)

Now, we need to find the specific heat capacity of lead (C). Unfortunately, the search results did not provide a direct value for the specific heat capacity of lead. However, we can assume that the specific heat capacity of lead is approximately 130 J/kg°C.

Using the formula, we can calculate the heat released:

Q = m * C * (T2 - T1)

Q = 1 kg * 130 J/kg°C * (17°C - 327°C)

Calculating the value:

Q = 1 kg * 130 J/kg°C * (-310°C)

Q = -40,300 J

Therefore, approximately 40,300 joules of heat will be released during the crystallization of 1 kg of lead, taken at a temperature of 327°C and cooled to 17°C.

Please note that the negative sign indicates that heat is being released during the process of crystallization.