Question

Ребят помоги пожалуйста,решите задачу: После повышения температуры на 9 градусов давление газа в закрытом балоне увеличилось на 3%.каокй была начальная температура?

Answer 1

p2 = 1,03 p1     |       Воспользуемся законом Шарля:

T2 = T1 + 282K |            p1/T1 = p2/T2

T1 = ????           |         Выразим из данной пропорции T1:

_______________            T1 = T2*p1/p2

                          Подставляя известные данные находим начальную температуру:

                                        1.03T1 = T1 + 282

                                         0.03T1 = 282 

                                          T1 = 9400 К

 

 

                                                                         Ответ: 9400 Кельвин

Answer 2

Problem Analysis

We are given that the temperature of a closed gas cylinder increased by 9 degrees Celsius, and as a result, the pressure of the gas increased by 3%. We need to find the initial temperature of the gas.

Solution

Let's assume the initial temperature of the gas is T degrees Celsius.

According to the problem, when the temperature increased by 9 degrees Celsius, the pressure increased by 3%.

We can use the formula for the relationship between temperature and pressure of an ideal gas, known as Charles's Law:

P1 / T1 = P2 / T2

Where: - P1 is the initial pressure of the gas - T1 is the initial temperature of the gas - P2 is the final pressure of the gas - T2 is the final temperature of the gas

In this case, we know that the final temperature is T + 9 degrees Celsius, and the final pressure is P1 + 3% of P1.

Substituting these values into the equation, we get:

(P1 + 3% of P1) / (T + 9) = P1 / T

Simplifying the equation, we can remove the percentage by dividing it by 100:

(P1 + 0.03P1) / (T + 9) = P1 / T

Multiplying both sides of the equation by T(T + 9) to eliminate the denominators, we get:

T(P1 + 0.03P1) = (P1)(T + 9)

Expanding the equation, we have:

TP1 + 0.03TP1 = TP1 + 9P1

Simplifying further, we get:

0.03TP1 = 9P1

Dividing both sides of the equation by P1, we get:

0.03T = 9

Dividing both sides of the equation by 0.03, we get:

T = 9 / 0.03

Calculating the value, we find:

T = 300

Therefore, the initial temperature of the gas was 300 degrees Celsius.

Answer

The initial temperature of the gas was 300 degrees Celsius.