Question

Керосин по каплям вытекает из бюретки через отверстие диаметром 2 мм,причем капли падают одна за другой с интервалом 1 с.За сколько времени вытечет 25 см^3 керосина?

Answer 1

Смею предположить, что (раз это задача) объем одной капли можно принять равной ОБЪЕМУ ШАРА с диаметром 2 мм (размер отверстия бюретки). 
Потом объем бюретки разделим на объем капель - узнаем количество капель в 25 см^3. А потом умножим это число на 1 секунду. 

V = 4/3 П R^3 = 4/3 * 3,14 * (1 мм)^3 = 4,19 мм^3 

1см^3 = 1000мм^3 

25 000 мм^3 / 4,19 мм^3 = 5966,6 (шт.) 
примерно за 5967 секунд = 99 мин. 27 сек.

Answer 2

Calculating the Time for Kerosene to Leak

To calculate the time it takes for 25 cm^3 of kerosene to leak through the 2 mm diameter hole in droplets, we can use the following approach:

1. Calculate the Volume of a Single Droplet: - The volume of a sphere can be calculated using the formula V = (4/3) * π * r^3, where r is the radius of the sphere. - In this case, the radius of the droplet can be calculated as half of the diameter, which is 1 mm or 0.1 cm.

2. Determine the Number of Droplets: - We can then calculate the number of droplets required to make up 25 cm^3 of kerosene.

3. Calculate the Time: - Finally, we can calculate the time it takes for these droplets to leak through the hole at an interval of 1 second.

Let's proceed with these calculations.

Calculations

1. Volume of a Single Droplet: - The volume of a single droplet can be calculated using the formula V = (4/3) * π * r^3, where r = 0.1 cm (radius of the droplet). - Substituting the value of r, we get V = (4/3) * π * (0.1)^3 = (4/3) * π * 0.001 = 0.004188 cm^3.

2. Number of Droplets: - To find the number of droplets required to make up 25 cm^3 of kerosene, we can divide the total volume by the volume of a single droplet. - Number of droplets = 25 cm^3 / 0.004188 cm^3 ≈ 5967 droplets.

3. Calculate the Time: - Since the droplets fall at an interval of 1 second, the time it takes for 5967 droplets to fall can be calculated as 5967 seconds.

Conclusion

Therefore, it would take approximately 5967 seconds for 25 cm^3 of kerosene to leak through the 2 mm diameter hole in droplets, with each droplet falling at a 1-second interval.