Question

за какое время в нити накала электрической лампы сопротивлением 25 Ом и силе тока в ней 0,2 А выделяется 600 Дж количество теплоты?

Answer 1

Q (количество теплоты) = I ^2(сила тока в квадрате) *R(сопротивление) *t(время)

t = Q / І^2 *R = 600 Дж / 0,04 А^2 * 25 Ом = 0,06 * 10^4c. = 600с. 

Answer 2

Дано:
R=25 Ом.

I=0,2 А.

Q=600 Дж.

t=?

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Решение:
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Answer 3

Calculation of Heat Energy in an Electric Lamp

To calculate the amount of heat energy released in an electric lamp, we can use the formula:

Q = I^2 * R * t

Where: - Q is the heat energy released (in joules) - I is the current flowing through the lamp (in amperes) - R is the resistance of the lamp (in ohms) - t is the time for which the lamp is on (in seconds)

In this case, we are given: - Resistance (R) = 25 ohms - Current (I) = 0.2 A - Heat energy (Q) = 600 J

We need to find the time (t) for which the lamp is on.

Using the formula, we can rearrange it to solve for time (t):

t = Q / (I^2 * R)

Substituting the given values:

t = 600 J / (0.2 A)^2 * 25 Ω

Calculating the value:

t = 600 J / (0.04 A^2 * 25 Ω) t = 600 J / (0.001 Ω) t = 600,000 seconds

Therefore, the lamp is on for 600,000 seconds to release 600 joules of heat energy.

Please note that the calculation assumes a constant current flow and a constant resistance throughout the operation of the lamp.