Question

Какое количество теплоты выделится при конденсации 500 г спирта, взятого при температуре 78 градусов цельсия (С фурмулами)

Answer 1

Спирт кипит и конденсируется при температуре 78 град Ц. При этом выделяется количество теплоты, равное Q = m r; где удельная теплота парообразования и конденсации равна r = 850 000 Дж/кг; поэтому
Q = 0,5 кг * 850 000 Дж/кг = 425 000 Дж = 425 кДж. 

Answer 2

Calculating Heat Released During Condensation of 500g of Alcohol

To calculate the amount of heat released during the condensation of 500g of alcohol, we can use the formula:

q = m * ΔHvap

Where: - q = heat released (in joules) - m = mass of the substance (in grams) - ΔHvap = heat of vaporization (in J/g)

First, we need to find the heat of vaporization for alcohol.

Heat of Vaporization of Alcohol

The heat of vaporization for alcohol varies depending on the specific type of alcohol. For example, the heat of vaporization of ethanol (ethyl alcohol) is approximately 841 J/g [[1]].

Calculation

Using the heat of vaporization for ethanol (841 J/g), we can calculate the heat released during the condensation of 500g of alcohol at 78 degrees Celsius.

q = 500g * 841 J/g = 420,500 J

Therefore, the amount of heat released during the condensation of 500g of alcohol at 78 degrees Celsius is approximately 420,500 joules.