
Помогите пожалуйста решить задачу.В однородном магнитном поле с индукцией B=5*10^(-2) Тл
перемещается проводник длиной L=0.8м. Сила тока в проводнике I=15A. Проводник расположен под углом =30 градусов к вектору магнитной индукции. Найдите силу, действующую на проводник, и работу магнитного поля по перемещению проводника на расстояние s=1.8м.

Ответы на вопрос




To solve this problem, we can use the formula for the force on a current-carrying conductor in a magnetic field:
F = BILsinθ
where: - F is the force on the conductor, - B is the magnetic field strength (induction), - I is the current in the conductor, - L is the length of the conductor, - θ is the angle between the conductor and the magnetic field.
Given: - Magnetic field strength (induction) B = 5 * 10^(-2) Tl - Length of the conductor L = 0.8 m - Current in the conductor I = 15 A - Angle between the conductor and the magnetic field θ = 30 degrees - Displacement of the conductor s = 1.8 m
Calculating the Force on the Conductor:
Using the formula F = BILsinθ, we can calculate the force on the conductor.F = (5 * 10^(-2) Tl) * (15 A) * (0.8 m) * sin(30 degrees)
Evaluating the above expression, we find:
F ≈ 0.2 N
Therefore, the force acting on the conductor is approximately 0.2 Newtons.
Calculating the Work Done by the Magnetic Field:
The work done by the magnetic field on the conductor can be calculated using the formula:W = F * s * cosθ
where: - W is the work done by the magnetic field, - F is the force on the conductor, - s is the displacement of the conductor, - θ is the angle between the force and the displacement.
Given: - Force on the conductor F = 0.2 N - Displacement of the conductor s = 1.8 m - Angle between the force and the displacement θ = 30 degrees
Using the formula, we can calculate the work done:
W = (0.2 N) * (1.8 m) * cos(30 degrees)
Evaluating the above expression, we find:
W ≈ 0.31 J
Therefore, the work done by the magnetic field on the conductor is approximately 0.31 Joules.
Please let me know if you need any further assistance!


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