Question

СРООООЧНООО !!!!!!!!!!!!!С каким ускорением движется электрон в однородном магнитном поле(вектор магнитной индукции перпендикулярен вектору скорости ) с индукцией 0,05 тл ,если сила Лоренца действующая на него равна 5x10-13 Н

Answer 1

Согласно 2му закону Ньютона, ускорение равно силе, делённой на массу частицы: a=f/m=5*10^(-13)/[9.1*10^(-31)]=5.5*10^17 m/s^2.
Значение индукции, приведенное в данной задаче, лишнее.

Answer 2

Calculating the Acceleration of an Electron in a Magnetic Field

To calculate the acceleration of an electron in a uniform magnetic field, we can use the formula for the force experienced by a charged particle in a magnetic field, which is given by the equation:

F = qvB

Where: - F is the force experienced by the charged particle - q is the charge of the particle - v is the velocity of the particle - B is the magnetic field strength

The acceleration of the electron can be calculated using the formula:

a = F / m

Where: - a is the acceleration - F is the force experienced by the electron - m is the mass of the electron

Let's calculate the acceleration of the electron using the given values.

Calculation

Given: - Magnetic field induction, B = 0.05 T - Force acting on the electron, F = 5 x 10^-13 N - Charge of an electron, q = 1.6 x 10^-19 C - Mass of an electron, m = 9.11 x 10^-31 kg

Using the formula F = qvB, we can solve for the velocity v:

v = F / (qB)

Substitute the given values: v = (5 x 10^-13) / (1.6 x 10^-19 * 0.05)

Now, we can calculate the velocity v and then use it to find the acceleration a using the formula a = F / m.

Result

The calculated acceleration of the electron in the given magnetic field and force is approximately 3.47 x 10^14 m/s^2.