Question

РЕБЯТА,НА ВАС ОДНА НАДЕЖДА!!!На одной чашке рычажных весов находится груз весом 1,2 Н, на другой – весом 1,1 Н. На каком расстоянии (в мм) от центра коромысла весов надо подвесить гирьку весом 0,4 Н, чтобы весы были в равновесии? Длина коромысла 0,2 м.

Answer 1

Решение:
M1=M2+M3
1,2L=1,1L+0,4x
0,1L=0,4x
x=1/4L
x=0,25*0,1
х=0,025м

Answer 2

Calculation of the Distance from the Center of the Lever Arm

To determine the distance from the center of the lever arm where the weight of 0.4 N should be suspended in order to achieve equilibrium, we can use the principle of moments. The principle of moments states that for an object to be in equilibrium, the sum of the clockwise moments must be equal to the sum of the anticlockwise moments.

In this case, we have a lever arm with a weight of 1.2 N on one side and a weight of 1.1 N on the other side. We need to find the distance from the center of the lever arm where a weight of 0.4 N should be suspended to balance the lever arm.

Let's denote the distance from the center of the lever arm to the weight of 1.2 N as x1, and the distance from the center of the lever arm to the weight of 1.1 N as x2. We need to find the distance from the center of the lever arm to the weight of 0.4 N, which we'll denote as x3.

According to the principle of moments, we can write the equation:

Sum of clockwise moments = Sum of anticlockwise moments

(1.2 N) * (x1) = (1.1 N) * (x2) + (0.4 N) * (x3)

We know that the length of the lever arm is 0.2 m. Therefore, we can substitute x1 = 0.2 - x2 into the equation:

(1.2 N) * (0.