Question

Кусок льда массой 0.8 кг нагревают от -20 С до 0 С. При этом затрачено теплоты 33,6 кДж. Определить теплоёмкость куска льда в этом процессе и удельную теплоёмкость льда, если плавление не происходит

Answer 1

Q=cmt
c=Q:(m*t)
c=33600:0.8:20=2100

Answer 2

Calculation of Heat Capacity and Specific Heat Capacity of Ice

To determine the heat capacity and specific heat capacity of the ice, we can use the formula:

Q = mcΔT

Where: - Q is the amount of heat transferred - m is the mass of the ice - c is the specific heat capacity of the ice - ΔT is the change in temperature

Given: - Mass of the ice (m) = 0.8 kg - Initial temperature (T1) = -20°C - Final temperature (T2) = 0°C - Heat transferred (Q) = 33.6 kJ

To find the heat capacity (C) of the ice, we can rearrange the formula:

C = Q / ΔT

Let's calculate the heat capacity and specific heat capacity of the ice:

1. Calculate the change in temperature: ΔT = T2 - T1 ΔT = 0°C - (-20°C) ΔT = 20°C

2. Calculate the heat capacity: C = Q / ΔT C = 33.6 kJ / 20°C C = 1.68 kJ/°C

Therefore, the heat capacity of the ice is 1.68 kJ/°C.

3. Calculate the specific heat capacity: To find the specific heat capacity (c), we divide the heat capacity (C) by the mass (m): c = C / m c = 1.68 kJ/°C / 0.8 kg c = 2.1 kJ/kg°C

Therefore, the specific heat capacity of the ice is 2.1 kJ/kg°C.

Please note that the calculations assume that the melting of the ice does not occur during the heating process, as mentioned in the question.