Question

в двух противоположных вершинах квадрата со стороной 30 см находятся одинаковые отрицательные заряды по - 5 на 10 в - 9 каждый . найти напряженность поля в двух других вершинах квадрата

Answer 1

Решение во вложении.

Answer 2

Calculation of Electric Field Intensity

To find the electric field intensity at the two other vertices of the square, we can use the formula for electric field intensity due to a point charge:

Electric Field Intensity (E) = (k * q) / r^2

Where: - k is the electrostatic constant, approximately equal to 8.99 x 10^9 Nm^2/C^2 - q is the charge - r is the distance from the charge to the point where the electric field is being calculated

Given that the charge at each vertex is -5 x 10^-9 C and the side length of the square is 30 cm, we can calculate the electric field intensity at the other vertices.

Let's calculate the electric field intensity at one of the other vertices.

Using the formula, we have: - k = 8.99 x 10^9 Nm^2/C^2 - q = -5 x 10^-9 C - r = diagonal of the square = 30 cm * sqrt(2) = 30 cm * 1.414 = 42.42 cm = 0.4242 m

Substituting the values into the formula, we get: Electric Field Intensity (E) = (8.99 x 10^9 Nm^2/C^2 * -5 x 10^-9 C) / (0.4242 m)^2

Calculating the above expression gives us the electric field intensity at one of the other vertices of the square.

Please note that the above calculation assumes that the charges at the vertices are point charges and that the square is in a vacuum.

Let me calculate the electric field intensity at one of the other vertices for you.