Question

Два резистора сопротивлением 10 Ом и 25 ом соединены последовательно и подключены к источнику электрической энергии, Э.Д.С . которого 24 В и внутренее сопротивление -1 Ом. Определить ток в цепи.

Answer 1

I=E/(R1+R2+r) - закон ома для замкнутой цепи

I=24/36=2/3 А

Answer 2

Используем закон Ома для полной цепи:

I=E/(R+r),

где r - это внутреннее сопротивление источника ЭДС, R - сопротивление нагрузки.

Нагрузка состоит из двух последовательно соединенных резисторов R1=10 Ом и R2=25 Ом. Для последовательного соединения имеем R=R1+R2

Тогда

I=E/(R1+R2+r)=24/(10+25+1)≈0,67 А

 

Ответ: 0,67 А

 

Answer 3

Calculation of Current in the Circuit

To determine the current in the circuit, we need to apply Ohm's Law and consider the total resistance in the circuit.

The two resistors, with resistances of 10 Ω and 25 Ω, are connected in series. When resistors are connected in series, their resistances add up to give the total resistance.

The total resistance (R_total) in the circuit can be calculated by adding the resistances of the individual resistors: R_total = R1 + R2

In this case, R1 = 10 Ω and R2 = 25 Ω, so the total resistance is: R_total = 10 Ω + 25 Ω = 35 Ω

Now, we can calculate the current (I) in the circuit using Ohm's Law: I = E / R_total

Where: - I is the current in the circuit, - E is the electromotive force (EMF) or voltage of the power source, and - R_total is the total resistance in the circuit.

In this case, the EMF of the power source is 24 V.

Substituting the values into the formula, we get: I = 24 V / 35 Ω

Calculating the value, we find that the current in the circuit is approximately 0.686 A.

Please note that the internal resistance of the power source (-1 Ω) was not considered in this calculation, as it was not specified how it is connected in the circuit. If the internal resistance is connected in series with the resistors, it should be included in the total resistance calculation.