Question

В сосуде находится 0,5 л воды и 300 г льда при температуре 0 градусов цельсия. После того как в сосуд впустили 90 г водяного пара при температуре 100 градусов цельсия, в нем установилась температура смеси 33 градуса цельсия. Определите темплоёмкость сосуда.

Answer 1

Дано m1=0,5 кг  m2=0,3 кг  t1=0C   m3=0,09 кг  t3=100 C  t=33C    C- ?

Q3=Q1+Q2+Q+C*(t-t1)
L*m3+c*m3*(100-33)=л*m2 +c*(m1+m2)*(33-0)+C(33-0)

C=(2,3*10^6*0,09+4200*0,09*77-3,4*10^5*0,3-4200*0,8*33)/33

Answer 2

Calculation of the Heat Capacity of the Container

To determine the heat capacity of the container, we need to calculate the amount of heat absorbed by the water, ice, and container during the process.

Let's break down the steps:

1. The initial state of the system: - Volume of water (Vw) = 0.5 L - Mass of ice (mi) = 300 g - Initial temperature (Ti) = 0 degrees Celsius

2. Heat absorbed by the water: - The heat absorbed by the water can be calculated using the formula: Qw = mw * cw * ΔTw, where mw is the mass of water, cw is the specific heat capacity of water, and ΔTw is the change in temperature of the water. - The specific heat capacity of water is approximately 4.18 J/g°C. - The change in temperature of the water can be calculated as ΔTw = Tf - Ti, where Tf is the final temperature of the mixture. - Since the final temperature is 33 degrees Celsius, ΔTw = 33 - 0 = 33 degrees Celsius. - The mass of water can be calculated as mw = Vw * ρw, where ρw is the density of water. - The density of water is approximately 1 g/mL or 1000 kg/m^3. - Therefore, mw = 0.5 L * 1000 g/L = 500 g. - Substituting the values into the formula, we get Qw = 500 g * 4.18 J/g°C * 33°C = 68970 J.

3. Heat absorbed by the ice: - The heat absorbed by the ice can be calculated using the formula: Qi = mi * ci * ΔTi, where mi is the mass of ice, ci is the specific heat capacity of ice, and ΔTi is the change in temperature of the ice. - The specific heat capacity of ice is approximately 2.09 J/g°C. - The change in temperature of the ice can be calculated as ΔTi = Tf - Ti, where Tf is the final temperature of the mixture. - Substituting the values into the formula, we get Qi = 300 g * 2.09 J/g°C * (33°C - 0°C) = 19674 J.

4. Heat absorbed by the container: - The heat absorbed by the container can be calculated using the formula: Qc = mc * cc * ΔTc, where mc is the mass of the container, cc is the specific heat capacity of the container, and ΔTc is the change in temperature of the container. - The specific heat capacity of the container is not provided in the question, so we cannot calculate this value accurately without additional information.

Therefore, we can calculate the total heat absorbed by the system as the sum of the heat absorbed by the water and the ice: Qtotal = Qw + Qi = 68970 J + 19674 J = 88644 J.

Unfortunately, without the specific heat capacity of the container, we cannot accurately determine the heat capacity of the container. Additional information is needed to calculate the heat capacity of the container.