
Грузовой поезд между двумя пунктами двигался со скоростью(средней) 60км.ч с учетом 2часовой
остановки. если же время остановки не учитывать, то пое3д двигался со средней скоростью 90км.ч. на какое растояние пое3д перевозил грузы?Решить задачу

Ответы на вопрос

S =v2*t
приравняем
v1(t+2) =v2*t
подставим данные
60(t+2) = 90t
60t+120 = 90t
120 =30t
t = 4 ч - время движения без остановки
S =v2*t = 90*4 =360 км
ОТВЕТ 360 км



To solve this problem, we need to find the distance traveled by the freight train between the two points. We are given two scenarios: one where the train travels at an average speed of 60 km/h with a 2-hour stop, and another where the stop time is not considered and the train travels at an average speed of 90 km/h.
Let's calculate the distance traveled in each scenario:
Scenario 1: Average speed of 60 km/h with a 2-hour stop
To find the distance, we need to calculate the time spent traveling and the time spent on the stop.
Let's assume the time spent traveling is t hours. Since the average speed is 60 km/h, the distance traveled during this time is 60t km.
The time spent on the stop is given as 2 hours.
Therefore, the total time taken for the journey is t + 2 hours.
Scenario 2: Average speed of 90 km/h without considering the stop time
In this scenario, the average speed is 90 km/h, and we are not considering the stop time.
Let's assume the time spent traveling in this scenario is t' hours. The distance traveled during this time is 90t' km.
Now, we need to find the relationship between t and t'.
Since the time spent on the stop is 2 hours, the time spent traveling in scenario 1 is t = t' + 2.
Now, we can equate the distances traveled in both scenarios:
60t = 90t'
Substituting t = t' + 2:
60(t' + 2) = 90t'
Simplifying the equation:
60t' + 120 = 90t'
Subtracting 60t' from both sides:
120 = 30t'
Dividing both sides by 30:
t' = 4
Now, we can find the distance traveled in scenario 2:
Distance = 90t' = 90 * 4 = 360 km
Therefore, the freight train transported the goods for a distance of 360 km.


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