Question

Мяч брошенный вниз с балкона с высоты h1=3м,отскочил от тратуара и поднялся на высоту h2=м относительно земли .определите модуль перемещения времени.

Answer 1

Перемещение = 3-2 = 1 (м)

Answer 2

Calculation of the Time Displacement

To determine the time displacement of the ball, we can use the principles of projectile motion. The ball is thrown downward from a height of h1 = 3m and then bounces back up to a height of h2 = 1m relative to the ground. We need to find the time it takes for the ball to reach this height.

The time it takes for an object to reach its maximum height and then fall back to the ground can be calculated using the equation:

t = 2 * sqrt(h / g)

Where: - t is the time of flight - h is the height - g is the acceleration due to gravity (approximately 9.8 m/s^2 on Earth)

Let's calculate the time displacement of the ball.

Using the given values: - h1 = 3m (height from which the ball is thrown downward) - h2 = 1m (height to which the ball bounces back up) - g = 9.8 m/s^2

For the downward motion: - h = h1 - h2 = 3m - 1m = 2m

For the upward motion: - h = h2 = 1m

Calculating the time for each motion: - t1 = 2 * sqrt(h1 / g) = 2 * sqrt(2m / 9.8 m/s^2) - t2 = 2 * sqrt(h2 / g) = 2 * sqrt(1m / 9.8 m/s^2)

Adding the times for both motions to get the total time displacement: - t_total = t1 + t2

Let's calculate the time displacement using the given values.

Using the formula above, we can calculate the time displacement of the ball.