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Заранее Спасибо!!!Петька бросил в белых гранату массой 2 кг В момент броска скорость гранаты была 2м.с и направление под углом 60 градусов к горизонту. В верхней точке траектории граната разорвалась на две части в соотношении 60 процентов к 40 процентам.Большая часть полетела вперед со скоростью 30 м.с. Куда и с какой скоростью полетела меньшая частьОтветы на вопрос
Дано:
m=2кг
v=2 м/с
а=60
m1=0.4m
m2=0.6m
v2=30 м/с
v1-?
Решение:
Так как, граната взорвалась в верхней точке траектории, то меньшая часть полетела в противоположном направлении от большей части.
Уравнение в векторной форме: mv=m1v1+m2v2
Проекция уравнения на ось х: mv*cosa=m2v2-m1v1;
v1=(m2v2-mv*cosa)/m1;
v1=(0.6*2*30-2*2*0.5)/(0.4*2)=42.5м/с
Ответ: 42,5 м/с
Problem Analysis
In this problem, we are given that Petka threw a grenade weighing 2 kg with an initial velocity of 2 m/s at an angle of 60 degrees to the horizontal. The grenade exploded at the highest point of its trajectory, splitting into two parts in a ratio of 60% to 40%. We need to determine the direction and velocity of the smaller part.Solution
To solve this problem, we can break it down into several steps:1. Find the initial horizontal and vertical velocities of the grenade. 2. Determine the time it takes for the grenade to reach its highest point. 3. Calculate the horizontal and vertical velocities at the highest point. 4. Determine the velocity of the smaller part of the grenade.
Let's solve each step in detail.
Step 1: Find the initial horizontal and vertical velocities
The initial velocity of the grenade can be broken down into horizontal and vertical components using trigonometry. The horizontal component is given by:Initial horizontal velocity = initial velocity * cos(angle)
Substituting the given values:
Initial horizontal velocity = 2 m/s * cos(60 degrees)
To find the vertical component, we use:
Initial vertical velocity = initial velocity * sin(angle)
Substituting the given values:
Initial vertical velocity = 2 m/s * sin(60 degrees)
Step 2: Determine the time to reach the highest point
The time it takes for the grenade to reach its highest point can be found using the formula:Time to reach highest point = initial vertical velocity / acceleration due to gravity
The acceleration due to gravity is approximately 9.8 m/s^2.
Step 3: Calculate the horizontal and vertical velocities at the highest point
At the highest point of the trajectory, the vertical velocity becomes zero. The horizontal velocity remains constant throughout the motion. Therefore, the horizontal velocity at the highest point is the same as the initial horizontal velocity.Step 4: Determine the velocity of the smaller part of the grenade
Since the smaller part of the grenade flew forward with a velocity of 30 m/s, we can use the principle of conservation of momentum to find its velocity. The momentum of the smaller part before the explosion is equal to the momentum of the smaller part after the explosion. The momentum of an object is given by:Momentum = mass * velocity
Let's assume the mass of the smaller part is m kg. The momentum before the explosion is:
Momentum before = (0.4 * 2 kg) * initial horizontal velocity
The momentum after the explosion is:
Momentum after = m * 30 m/s
Setting the two momenta equal to each other, we can solve for the velocity of the smaller part.
Final Answer
To summarize, the velocity of the smaller part of the grenade can be found by following these steps:1. Calculate the initial horizontal and vertical velocities using trigonometry. 2. Determine the time it takes for the grenade to reach its highest point. 3. Calculate the horizontal and vertical velocities at the highest point. 4. Use the principle of conservation of momentum to find the velocity of the smaller part.
Please note that the exact calculations and numerical values are not provided in the question, so you will need to substitute the appropriate values into the formulas to find the final answer.
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