Question

Helllpppp...Знаю ответ,а как решить .... ВоHelllpppp...Знаю ответ,а как решить .... Во сколько раз период обращения спутника, движущегося на расстоянии 21600 км от поверхности Земли, больше периода обращения спутника, движущегося на расстоянии 600 км от ее поверхности? Радиус Земли принять равным 6400 км. (Ответ 8).Прошу прописать как вышло и что к чему,заранее спасибо

Answer 1

Решется по закону двоцентр. ускор.
A(доцентр)=скор/радиус хемли+высота
Fдоцентрове=а*масу
v=[гамма маса земли/радиус земли+ высота]корень квадр.
l=2pr=2p(радиус земли +высота h)
h1=21600+6400=28000
h2=600+6400=7000
Росщитываем по периодам
Т=2p(Rземли+выс h)/ [гамма Маса земли/Rземли+h]
T1=2p(Rземли+h1)*[Rземли+h1]корень квадр/[гамма Маса земли] корень кв.
Т2= 2p(Rземли+h2)*[Rземли+h2]корень квадр/[гамма Маса земли] корень кв.
Делим: Т2/Т1= (гаммы маса земли сокращаются)=(Rземли+h2)*[Rземли+h2]корень кв / (Rземли+h1)*[ Rземли+h1]корень кв=7000*[7000]кор кв/28000*[28000]кор кв= (сокращаэться 7000 и 28000) 1/4*[1/4] кор кв= 1/4*1/2=1/8
Выходит что Т2 к Т1 как 1 к 8, тоесть больше в 8 раз
P.S. за эту можно было б и больше чем 12 пкт дать))

Answer 2

To solve this problem, we need to compare the periods of two satellites: one moving at a distance of 21,600 km from the surface of the Earth and the other moving at a distance of 600 km from the surface of the Earth. The radius of the Earth is given as 6,400 km.

Calculating the Period of the First Satellite

The period of a satellite is the time it takes for the satellite to complete one full orbit around the Earth. We can calculate the period using the formula:

T = 2π√(r³/GM)

Where: - T is the period of the satellite - r is the distance between the satellite and the center of the Earth - G is the gravitational constant (approximately 6.67430 × 10^-11 m³ kg^-1 s^-2) - M is the mass of the Earth (approximately 5.972 × 10^24 kg)

For the first satellite, the distance from the surface of the Earth is 21,600 km + 6,400 km (radius of the Earth) = 28,000 km.

Converting the distance to meters, we get: 28,000 km = 28,000,000 meters

Plugging the values into the formula, we get: T₁ = 2π√((28,000,000)³/(6.67430 × 10^-11 × 5.972 × 10^24))

Calculating this value gives us the period of the first satellite.

Calculating the Period of the Second Satellite

For the second satellite, the distance from the surface of the Earth is 600 km + 6,400 km (radius of the Earth) = 7,000 km.

Converting the distance to meters, we get: 7,000 km = 7,000,000 meters

Plugging the values into the formula, we get: T₂ = 2π√((7,000,000)³/(6.67430 × 10^-11 × 5.972 × 10^24))

Calculating this value gives us the period of the second satellite.

Comparing the Periods

To find the ratio of the periods, we divide the period of the first satellite by the period of the second satellite:

Ratio = T₁ / T₂

If the ratio is greater than 1, then the period of the first satellite is greater than the period of the second satellite.

If the ratio is equal to 1, then the periods of both satellites are equal.

If the ratio is less than 1, then the period of the first satellite is less than the period of the second satellite.

By comparing the periods, we can determine how many times the period of the first satellite is greater than the period of the second satellite.

Please note that the calculations provided above are based on the given information and assumptions. If there are any additional details or considerations, please let me know and I'll be happy to assist you further.