Question

С какой по модулю скоростью должен лететь самолет в верхней точке мертвой петли чтобы летчик был полностью невесомым, если радиус петли 360м? чему равно время одного полного оборота? срочно помогите 30баллов дам!!!

Answer 1

P=0  если a=g=9,8 м/с2

a=V^2/R

V=√g*R=√3600=60 м/с

T=L/V=2*п*R/V=6,28*360/60=37,7 с

Ответ V=60 м/с

Answer 2

Speed of the airplane in the top point of a loop-the-loop

To determine the speed at which the pilot of an airplane would be completely weightless in the top point of a loop-the-loop, we can use the concept of centripetal force. In this case, the centripetal force is provided by the gravitational force acting on the pilot.

The formula for centripetal force is:

F = m * v^2 / r

Where: - F is the centripetal force - m is the mass of the pilot - v is the velocity of the airplane - r is the radius of the loop-the-loop

In the top point of the loop-the-loop, the gravitational force acting on the pilot is equal to the centripetal force. Therefore, we can equate the two forces:

m * g = m * v^2 / r

Simplifying the equation, we can solve for v:

v = sqrt(g * r)

Where: - g is the acceleration due to gravity (approximately 9.8 m/s^2) - r is the radius of the loop-the-loop (360 m)

Substituting the values into the equation, we get:

v = sqrt(9.8 * 360) ≈ 60.0 m/s

Therefore, the airplane should be flying at a speed of approximately 60.0 m/s in the top point of the loop-the-loop to make the pilot completely weightless.

Time for one complete revolution

To calculate the time for one complete revolution, we can use the formula for the period of circular motion:

T = 2πr / v

Where: - T is the period (time for one complete revolution) - r is the radius of the loop-the-loop (360 m) - v is the velocity of the airplane (60.0 m/s)

Substituting the values into the equation, we get:

T = 2π * 360 / 60.0 ≈ 37.7 s

Therefore, the time for one complete revolution is approximately 37.7 seconds.

I hope this helps! Let me know if you have any further questions.