Question

Если тело массой 3 кг подвесить к динамометру , пружина растянется на 6 см . Ребенок подвесил к динамометру другое тело и пружина удлинилась на 4,2 см. Чему равна масса подвешенного тела?

Answer 1

Составим пропорцию:
3 кг - 6 см
х кг - 4,2 см
Теперь решаем как пропорцию: произведение крайних членов равно произведению средних: 3*4,2=х*6
х*6=12,6
х=12,6:6
х=2,1
Ответ: 2,1 кг

Answer 2

Calculation of the Mass of the Suspended Object

To calculate the mass of the suspended object, we can use Hooke's Law, which states that the force exerted by a spring is directly proportional to the displacement of the spring from its equilibrium position. The formula for Hooke's Law is:

F = kx

Where: - F is the force exerted by the spring - k is the spring constant - x is the displacement of the spring from its equilibrium position

In this case, we are given that the spring elongates by 6 cm (0.06 m) when a 3 kg object is suspended from it. Let's assume the spring constant is denoted by k.

Using Hooke's Law, we can write the equation as:

F = kx

Substituting the given values, we have:

F = k * 0.06

Now, let's consider the second scenario where a different object is suspended from the dynamometer and the spring elongates by 4.2 cm (0.042 m). Let's assume the mass of the second object is denoted by m.

Again, using Hooke's Law, we can write the equation as:

F = k * 0.042

Since the force exerted by the spring is the same in both scenarios, we can equate the two equations:

k * 0.06 = k * 0.042

Simplifying the equation, we get:

0.06k = 0.042k

Dividing both sides by k (assuming k is not equal to 0), we have:

0.06 = 0.042

Therefore, the mass of the suspended object is not determined by the given information.