Question

К концам невесомого рычага подвешены грузы весом 2 H и 12 H. Расстояние от точки опоры до большего груза равно 2 см.Определите длину рычага, если рычаг находиться в равновесии. ПОМОГИТЕ

Answer 1

Длина рычага х=х1+х2
в рычаге более массивный груз лежит ближе к оси вращения.
12*x1=2*x2  
12*2=2*x2   x2=12cм
общая длина рычага 2+12=14 см

Answer 2

Problem Analysis

We are given a lever with two weights attached to its ends. The weight of the larger weight is 12H, and the weight of the smaller weight is 2H. The distance from the pivot point to the larger weight is 2 cm. We need to determine the length of the lever if it is in equilibrium.

Solution

To solve this problem, we can use the principle of moments. The principle of moments states that for an object to be in equilibrium, the sum of the clockwise moments must be equal to the sum of the anticlockwise moments.

Let's assume the length of the lever is L. The clockwise moment is given by the product of the weight and the distance from the pivot point, while the anticlockwise moment is given by the product of the weight and the distance from the pivot point.

We can set up the following equation based on the principle of moments:

12H * 2cm = 2H * (L - 2cm)

Simplifying the equation, we get:

24H = 2H * L - 4H

Adding 4H to both sides of the equation, we get:

24H + 4H = 2H * L

Simplifying further, we get:

28H = 2H * L

Dividing both sides of the equation by 2H, we get:

L = 14 cm

Therefore, the length of the lever is 14 cm.

Answer

The length of the lever is 14 cm.