Question

При вертикальном подъеме груза массой 1 кг и весом 20H на высоту 1 м была совершена работа 80Дж. С каким ускорением поднимали груз?

Answer 1

При подъеме груза совершается работа, равная A = Fh cosα. Т. к. α = 0, то сos α = 1, тогда A = Fh -> F=A/h. Силу F можно найти из уравнения динамики F – mg = ma; Подставим
A/h-mg=ma-> a=A/(hm)-g=30/(2*1)-10= 5

Ответ 4) 5 м/с2

Answer 2

Calculation of Acceleration

To determine the acceleration at which the load was lifted, we can use the work-energy principle. The work done on an object is equal to the change in its kinetic energy. In this case, the work done is given as 80 J, and the mass of the load is 1 kg.

The formula for work is:

Work = Force x Distance

In this case, the force is the weight of the load, which is given as 20 H (20 N), and the distance is 1 m.

So, we have:

80 J = 20 N x 1 m

To find the acceleration, we can use Newton's second law of motion, which states that the force acting on an object is equal to the mass of the object multiplied by its acceleration:

Force = Mass x Acceleration

In this case, the force is 20 N and the mass is 1 kg. Rearranging the formula, we get:

Acceleration = Force / Mass

Substituting the values, we have:

Acceleration = 20 N / 1 kg = 20 m/s^2

Therefore, the load was lifted with an acceleration of 20 m/s^2.