Question

Два проводника соединены параллельно сила тока в первом проводнике 0.5 а, во втором 0,3 а. напряжение на участке 120 в. определить силу тока на всем участке цепи и полное сопротивление участка

Answer 1

Возможно не правильно, кто решит скажите верно или нет.
I1 = 0.5 A
I2 = 0.3 A
U = 120 B
I = I1 + I2 = 0.5 + 0.3 = 0.8 A
Необходимо найти R1 и R2 
R1 = U/I1 = 120/0.5 = 240 ом
R2 = U/I2 = 120/0.3 = 400 ом 
1/R = 1/R1 + 1/R2 = 1/240 ом + 1/400 ом = 8/1200 ом = 2/300 ом =>
R = 300/2 = 150 ом 

Answer 2

Calculation of Total Current and Total Resistance

To determine the total current and total resistance in the circuit, we need to consider the two parallel conductors.

Given: - Current in the first conductor (I₁) = 0.5 A - Current in the second conductor (I₂) = 0.3 A - Voltage across the segment (V) = 120 V

To find the total current (I_total) in the circuit, we can add the currents in the two parallel conductors:

I_total = I₁ + I₂

Substituting the given values:

I_total = 0.5 A + 0.3 A = 0.8 A

Therefore, the total current in the circuit is 0.8 A.

To find the total resistance (R_total) in the circuit, we can use Ohm's Law:

R_total = V / I_total

Substituting the given values:

R_total = 120 V / 0.8 A = 150 Ω

Therefore, the total resistance in the circuit is 150 Ω.

Conclusion

The total current in the circuit is 0.8 A, and the total resistance is 150 Ω.