Question

На тіло , яке має заряд 6*10 в минус 8-ой Кл , діє сила 1,2 * 10 в минус 5-ой Н. Яка напруженість електричного поля в цій точці ?

Answer 1

Треба розділити силу на заряд,тобто:

1.2*10в-5/6*10в-8=200Н/Кл 

Answer 2

Calculation of Electric Field Intensity

To calculate the electric field intensity at a point, we can use the formula:

Electric Field Intensity (E) = Force (F) / Charge (q)

Given: - Charge (q) = 6 * 10^(-8) C - Force (F) = 1.2 * 10^(-5) N

Substituting the given values into the formula, we can calculate the electric field intensity:

E = F / q

E = (1.2 * 10^(-5) N) / (6 * 10^(-8) C)

Simplifying the expression:

E = 20 N/C

Therefore, the electric field intensity at the given point is 20 N/C.