Question

Конденсатор емкостью 800 мкФ включен в сеть пере­менного тока с частотой 50 Гц с помощью проводов, со­противление которых 3 Ом. Какова сила тока в конденса­торе, если напряжение в сети 120 В?

Answer 1

Rc = 1/(2*π*f*c), где Rc - сопротивление конд. переменному току, f - частота тока, c - ёмкость конд. 
Rc = 1/(2*3.14*50*0.0008) = 3.981 (Ом);
Добавим к этому сопротивлению сопротивл. проводов:
3,981 + 3 = 6,981 (Ом);
I = U/R, I = 120 / 6.981 = 17.19 (A).
Ответ: I = 17,19 А.

Answer 2

Calculation of Current in the Capacitor

To calculate the current in the capacitor, we need to use the formula:

I = C * dV/dt

Where: - I is the current in the capacitor, - C is the capacitance of the capacitor, - dV/dt is the rate of change of voltage with respect to time.

In this case, the capacitance of the capacitor is given as 800 μF (microfarads), and the voltage in the circuit is 120 V. We need to find the current in the capacitor.

To find the rate of change of voltage with respect to time, we can use the formula:

dV/dt = V * 2πf

Where: - V is the voltage in the circuit, - f is the frequency of the alternating current.

In this case, the frequency is given as 50 Hz.

Let's calculate the current in the capacitor step by step:

1. Calculate the rate of change of voltage with respect to time: - V = 120 V - f = 50 Hz

dV/dt = V * 2πf

2. Calculate the current in the capacitor: - C = 800 μF - dV/dt = (V * 2πf) = (120 * 2π * 50)

I = C * dV/dt

Please note that the resistance of the wires (3 Ω) mentioned in the question is not relevant to the calculation of the current in the capacitor.

Let's calculate the current in the capacitor using the given values:

1. Calculate the rate of change of voltage with respect to time: - V = 120 V - f = 50 Hz

dV/dt = 120 * 2π * 50 = 37,699.11 V/s

2. Calculate the current in the capacitor: - C = 800 μF = 800 * 10^-6 F - dV/dt = 37,699.11 V/s

I = (800 * 10^-6) * 37,699.11 = 30.1593 A

Therefore, the current in the capacitor is approximately 30.1593 A.