Question

Из двух городов А и В, расположенных один от другого на расстоянии 54 км выехали одновременно в одном направлении два мотоциклиста: первый из А со скоростью 72 км ч, второй из В со скоростью 54 км ч через сколько времени и на каком расстоянии от города А первый мотоциклист догонит второго?

Answer 1

1)72-54=18(км/ч)-разность скоростей автомобилей

2)20:18=10/9(ч)-время в пути

3)54* 10/9=60(км)-прошел 2

Answer 2

Problem Analysis

We are given two cities, A and B, located 54 km apart. Two motorcyclists start simultaneously from these cities and travel towards each other. The first motorcyclist starts from city A with a speed of 72 km/h, while the second motorcyclist starts from city B with a speed of 54 km/h. We need to determine the time it takes for the first motorcyclist to catch up to the second motorcyclist and the distance from city A at which this happens.

Solution

To solve this problem, we can use the formula: time = distance / speed.

Let's assume that the first motorcyclist catches up to the second motorcyclist after time 't' hours.

During this time, the first motorcyclist will travel a distance of 72t km, and the second motorcyclist will travel a distance of 54