Question

Вагон весом P=1,90 движиется с началной скоростью Vo=10 . Определить среднюю силу , действущую на вагон , если известно , что вагон останавливается через t c ?

Answer 1

Вагон движется равнозамедленно. Применим закон движения и второй закон Ньютона:
$a=\frac{v_0}{t}\\ a=\frac{F}{m}=\frac{F}{\frac{P}{g}}=g\frac{F}{P}\\\\ \frac{v_0}{t}=g\frac{F}{P}\\ F=\frac{Pv_0}{gt}$

В Вашем вопросе не сказано в каких единицах измерения даны скорость и вес, так что я предположу что вагон микроскопический, и его вес - 1,9 Н, а скорость 10 м/c. Тогда ответ будет 1,9*10/(10*t)=1,9/t.

Answer 2

Problem Analysis

We are given the following information: - The mass of the wagon, P, is 1.90. - The initial velocity of the wagon, Vo, is 10. - The wagon comes to a stop in time t.

We need to determine the average force acting on the wagon during the stopping process.

Solution

To find the average force acting on the wagon, we can use Newton's second law of motion, which states that the force acting on an object is equal to the mass of the object multiplied by its acceleration.

In this case, the wagon is coming to a stop, so its final velocity, Vf, is 0. The acceleration, a, can be calculated using the equation of motion:

Vf = Vo + at

Since Vf = 0, we can rearrange the equation to solve for a:

a = -Vo / t

Now, we can calculate the force using Newton's second law:

F = P * a

Substituting the value of a, we get:

F = P * (-Vo / t)

Let's calculate the force using the given values.

Calculation

Given: - P = 1.90 (mass of the wagon) - Vo = 10 (initial velocity of the wagon) - t = ?

Using the equation F = P * (-Vo / t), we can solve for F.

F = 1.90 * (-10 / t)

Answer

The average force acting on the wagon during the stopping process is -19 / t.

Please provide the value of t to calculate the exact force.