Question

Тело массой m1 = 490 г лежит на горизонтальной поверхности. В него попадает и застревает пуля массой m2 = 10 г, летевшая в горизонтальном направлении со скоростью v2 = 500 м/с. Коэффициент трения между телом и поверхностью k = 0,2. Определить расстояние l, которое пройдет тело до остановки.

Answer 1

m₁=0.49 кг

m₂=0.01 кг

V₂=500 м/с

f=0.2

m₂V₂=(m₂+m₁)V₁  импульс тел mобщ=(m₂+m₁)=0.5 кг

V₁=m₂V₂/mобщ=0.01*500/0.5=10 м/с скорость тела с пулей после того когда пуля застряла в теле.

F-Fтр=0

mобщ*a-f*mобщ*g=0

0,5*а-0,2*0,5*10=0

а=0,2*0,5*10/0,5=2 м/с² ускорение тела с пулей

V=at

t=V/a=10/2=5 c время остановки тела

S=Vt=10*5=50 м

Answer 2

Problem Analysis

We are given the following information: - Mass of the body, m1 = 490 g - Mass of the bullet, m2 = 10 g - Velocity of the bullet, v2 = 500 m/s - Coefficient of friction between the body and the surface, k = 0.2

We need to determine the distance, l, that the body will travel before coming to a stop.

Solution

To solve this problem, we can use the principle of conservation of momentum. The initial momentum of the bullet is equal to the final momentum of the bullet and the body combined.

The initial momentum of the bullet is given by: p_initial = m2 * v2

The final momentum of the bullet and the body combined is given by: p_final = (m1 + m2) * v_final

Since the body comes to a stop, the final velocity, v_final, is 0.

Setting the initial momentum equal to the final momentum, we have: m2 * v2 = (m1 + m2) * 0

Simplifying the equation, we get: m2 * v2 = 0

Since the mass of the bullet and the velocity of the bullet are both non-zero, this equation cannot be satisfied. Therefore, the body will not come to a stop.

The body will not come to a stop.

Please let me know if I can help you with anything else.