Question

Сила притяжения между двумя одинаковыми шарами равна 1,67*10^-9Н. КАКОВА МАССА КАЖДОГО ШАРА,ЕСЛИ РАССТОЯНИЕ МЖДУ ИХ ЦЕНТРАМИ РАВНО 30 СМ? ГРАВИТАЦИОННАЯ постоянная равна 6,67*10^-11 Н м/кг^2 Если можно, полное решение

Answer 1

Формула всемирного тяготения: F=Gm^2/r^2.
выражаем массу: m=sqrt(F/G)*r
подставляем числа: m=sqrt(1,67*10^-9/6,67*10^-11)*0,3
ответ: m=1,5кг
P.S: наверно ты знаешь, что sqrt это "квадратный корень"

Answer 2

Calculation of the Mass of Each Sphere

To calculate the mass of each sphere, we can use the formula for gravitational force:

F = (G * m1 * m2) / r^2

Where: - F is the gravitational force between the two spheres, - G is the gravitational constant (6.67 * 10^-11 N m^2/kg^2), - m1 and m2 are the masses of the two spheres, and - r is the distance between the centers of the spheres.

In this case, we are given the gravitational force (1.67 * 10^-9 N) and the distance between the centers of the spheres (30 cm = 0.3 m). We need to find the mass of each sphere.

Let's solve for the mass of one sphere (m1) using the given information:

1.67 * 10^-9 N = (6.67 * 10^-11 N m^2/kg^2 * m1 * m1) / (0.3 m)^2

Simplifying the equation:

1.67 * 10^-9 N = (6.67 * 10^-11 N m^2/kg^2 * m1^2) / 0.09 m^2

Cross-multiplying:

1.67 * 10^-9 N * 0.09 m^2 = 6.67 * 10^-11 N m^2/kg^2 * m1^2

Dividing both sides by (6.67 * 10^-11 N m^2/kg^2):

(1.67 * 10^-9 N * 0.09 m^2) / (6.67 * 10^-11 N m^2/kg^2) = m1^2

Taking the square root of both sides:

sqrt((1.67 * 10^-9 N * 0.09 m^2) / (6.67 * 10^-11 N m^2/kg^2)) = m1

Calculating the value:

m1 ≈ 0.000003 kg

Therefore, the mass of each sphere is approximately 0.000003 kg.

Please note that this is an approximate value, as the given gravitational force and distance are rounded.