Question

Какое количество вещества содержится в 3 метрах кубических газа при давлении 300 кПа и температуре 27 градусов?

Answer 1

итак

pv=vRT  Уравнение Менделеева

отсюда:

v=pV/RT

v=361,44моль

 

Answer 2

Calculation of the Amount of Substance in 3 Cubic Meters of Gas

To calculate the amount of substance in 3 cubic meters of gas at a pressure of 300 kPa and a temperature of 27 degrees Celsius, we can use the ideal gas law equation:

PV = nRT

Where: - P is the pressure of the gas (in pascals) - V is the volume of the gas (in cubic meters) - n is the amount of substance (in moles) - R is the ideal gas constant (8.314 J/(mol·K)) - T is the temperature of the gas (in Kelvin)

First, we need to convert the given temperature from Celsius to Kelvin: T(K) = T(°C) + 273.15

So, the temperature in Kelvin is: T = 27 + 273.15 = 300.15 K

Now, we can rearrange the ideal gas law equation to solve for the amount of substance (n): n = PV / RT

Substituting the given values: - P = 300 kPa = 300,000 Pa - V = 3 cubic meters - R = 8.314 J/(mol·K) - T = 300.15 K

We can now calculate the amount of substance (n):

n = (300,000 Pa) * (3 m^3) / (8.314 J/(mol·K) * 300.15 K)

Calculating this expression gives us the amount of substance in moles.

Please note that the search results provided do not directly answer the question. However, the calculation provided above is based on the ideal gas law, which is a fundamental principle in gas physics.