Question

Какой резистор надо соединить параллельно с резистором в 300 ом чтобы получить общее сопротивление 120ом определите силу тока идущую через каждый резистор если общая сила тока равна 6А. Начертите схему.

Answer 1

1/120=1/300+1/R₂ следовательно r=200 Ом
I₁/I₂=R₂/R₁,   I₂=I-I₁,   I₁/I-I₁=200/300, I₁=(2/3I)·3/5, I₁=2·6A/5=2,4A,  I₂=6A-2,4A=3,6A

Answer 2

Calculating Resistance and Current in a Parallel Circuit

To determine the resistor needed in parallel with a 300-ohm resistor to achieve a total resistance of 120 ohms and calculate the current flowing through each resistor, we can use the following steps:

1. Calculating the Equivalent Resistance: - The formula for calculating the total resistance in a parallel circuit is given by: ``` 1 / R_total = 1 / R1 + 1 / R2 ``` - Substituting the given values, we can solve for the second resistor (R2).

2. Calculating the Current: - Once we have the value of the second resistor, we can use Ohm's law to calculate the current flowing through each resistor.

3. Drawing the Circuit Diagram: - We can also visualize the circuit by drawing a simple schematic diagram.

Let's proceed with the calculations and the circuit diagram.

Calculating the Equivalent Resistance

Using the formula for the total resistance in a parallel circuit: ``` 1 / R_total = 1 / 300 + 1 / R2 ``` Solving for R2: ``` 1 / R2 = 1 / R_total - 1 / 300 R2 = 1 / (1 / R_total - 1 / 300) ``` Substituting the given total resistance (R_total = 120 ohms): ``` R2 = 1 / (1 / 120 - 1 / 300) R2 = 1 / (5 / 600) R2 = 600 / 5 R2 = 120 ohms ``` The resistor needed in parallel with the 300-ohm resistor to achieve a total resistance of 120 ohms is 120 ohms.

Calculating the Current

Given that the total current is 6A and the resistances are 300 ohms and 120 ohms, we can calculate the current flowing through each resistor using Ohm's law: ``` I = V / R ``` Assuming the voltage is constant across both resistors, the current through each resistor can be calculated using the respective resistance values.

For the 300-ohm resistor: ``` I1 = 6A * (300 ohms / 120 ohms) = 15A ``` For the 120-ohm resistor: ``` I2 = 6A * (120 ohms / 120 ohms) = 6A ``` The current flowing through the 300-ohm resistor is 15A, and the current flowing through the 120-ohm resistor is 6A.

Circuit Diagram

``` _____ 300Ω _____ | | | | | | |____120Ω____| ```

In this circuit, the resistors are connected in parallel, and the total current of 6A is split between the two resistors based on their individual resistance values.

I hope this helps! If you have further questions or need additional assistance, feel free to ask.