Question

Один конец пружинки жесткостью 100 Н/м привязан к потолку лифта, а к другому концу привязана гирька массой 100 г. Определить величину ускорения лифта, если пружинка удлинилась при движении лифта на 0,2 см.

Answer 1

F=kx k=100, x= 0,002,F=0,2, F=ma, a=F/m, a= 0,2/0,1=2

Answer 2

Calculating the Acceleration of the Elevator

To calculate the acceleration of the elevator, we can use the formula for the force exerted by the spring, which is given by Hooke's Law: F = kx, where F is the force, k is the spring constant, and x is the displacement from the equilibrium position.

The force exerted by the spring can be equated to the force required to accelerate the mass of the girk, which is given by Newton's second law: F = ma, where F is the force, m is the mass, and a is the acceleration.

By equating these two forces, we can solve for the acceleration of the elevator.

Calculation Steps

1. Calculate the force exerted by the spring using Hooke's Law: F = kx. 2. Equate this force to the force required to accelerate the mass of the girk: F = ma. 3. Solve for the acceleration a.

Solution

1. Using Hooke's Law: F = kx, where k is the spring constant and x is the displacement from the equilibrium position. 2. The force exerted by the spring is equal to the force required to accelerate the mass of the girk: F = ma. 3. Solving for the acceleration a will give us the value we need.

Conclusion

By following these steps and using the given values, we can determine the acceleration of the elevator.