Question

Помогите пожалуйста. Определите показание пружинных весов, если взвешать алюминиевый шар массой 6 кг, полность поргуженный в воду(в воду погружен только шар). Ответ может быть не совсем нормальный, предупреждаю. Решите пожалуйста, в школе на лето задали.

Answer 1

• весы покажут значение, численно равное весу данного шара в воде

• вес шара в воде уменьшается на величину веса вытесненной воды по закону Архимеда

○ P = mg - Fa = p(a) V g - p(в) g V = g V (p(a) - p(в))

• объем шара равен V = m/p(a). тогда

○ P = ((m g)/p(a)) * (p(a) - p(в))

○ P = (60/2710) * (2710 - 1000) ≈ 37.86 Н

Answer 2

В воздухе P=mg
Арх сила FA=gρжVп
Показ динам в воде Pв=mg-gρжVп=mg-gρжma/ρa
Pв=6*10-10*1000*6/2700=60-22.2=37.8 (Н)

Answer 3

Determining the Reading of the Spring Scale

To determine the reading of the spring scale when weighing an aluminum sphere fully submerged in water, we can use the principles of buoyancy and the relationship between the apparent weight of the object in water and its actual weight.

Buoyant Force and Apparent Weight: When an object is submerged in a fluid, it experiences a buoyant force equal to the weight of the fluid displaced by the object. This buoyant force reduces the apparent weight of the object when it is submerged in the fluid.

Calculation: The reading on the spring scale when the aluminum sphere is fully submerged in water can be determined by considering the apparent weight of the sphere in water. The apparent weight of the sphere in water will be its actual weight minus the buoyant force acting on it.

The buoyant force can be calculated using the formula: \[ F_{\text{buoyant}} = \rho_{\text{fluid}} \times V_{\text{submerged}} \times g \] where: - \( \rho_{\text{fluid}} \) is the density of the fluid (in this case, water), - \( V_{\text{submerged}} \) is the volume of the sphere submerged in water, and - \( g \) is the acceleration due to gravity.

The apparent weight of the sphere in water can be calculated as: \[ \text{Apparent weight in water} = \text{Actual weight} - F_{\text{buoyant}} \]

Conclusion

The reading on the spring scale when the aluminum sphere is fully submerged in water will be the apparent weight of the sphere in water, which is its actual weight minus the buoyant force acting on it. This calculation requires knowledge of the density of water and the volume of the sphere submerged in water.

I hope this helps! Let me know if you have further questions or need additional assistance.