Question

По наклонному помосту длиной 10,8 м и высотой 1,2 м поднимают груз массой 180 кг, прилагая силу в 250 Н. Определите КПД моста.

Answer 1

КПД=Аполезная/Aзатраченная*100%     А-работа

Сначала найдем A полезную : 

Ап=mgh(g=9,8-сила притяжения)

Ап=180*9,8*1,2=1764*1,2~2117Дж

Аз=F*S=250*10,8=2700Дж.

КПД=2117Дж/2700Дж*100%~0,78*100%=78% - КПД моста

Answer 2

Calculation of Efficiency (КПД) of the Inclined Ramp

To determine the efficiency (КПД) of the inclined ramp, we need to calculate the work input and work output.

The work input (Входная работа) is given by the formula:

Work input = Force × Distance

In this case, the force applied is 250 N and the distance is the length of the ramp, which is 10.8 m. Therefore, the work input is:

Work input = 250 N × 10.8 m

To calculate the work output (Выходная работа), we need to consider the weight being lifted and the height it is being lifted to. The weight being lifted is 180 kg, and the height is 1.2 m. The work output is given by the formula:

Work output = Weight × Height

Work output = 180 kg × 9.8 m/s^2 × 1.2 m

Now, we can calculate the efficiency (КПД) using the formula:

Efficiency (КПД) = (Work output / Work input) × 100%

Let's calculate the efficiency:

Efficiency (КПД) = (Work output / Work input) × 100%

Efficiency (КПД) = ((180 kg × 9.8 m/s^2 × 1.2 m) / (250 N × 10.8 m)) × 100%

Calculating the values:

Efficiency (КПД) = (2116.8 J / 2700 J) × 100%

Efficiency (КПД) ≈ 78.4%

Therefore, the efficiency (КПД) of the inclined ramp is approximately 78.4%.

Please note that the calculations provided are based on the given information and assumptions.