Question

ПРОШУ ПОМОГИТЕ РЕШИТЬ ЗАДАЧУ,ПОЖАЛУЙСТА!!!(если можно подробно) Ракета начинает двигаться ускоренно с ускорением 35м/с^2,определите путь котoрый она пройдет за 10сек и ее скорость.

Answer 1

S=at^2/2=35x100/2=1750m.V=at=350m/c

Answer 2

Problem Analysis

We are given the acceleration of a rocket, which is 35 m/s^2. We need to find the distance it will travel in 10 seconds and its final velocity.

Solution

To find the distance traveled by the rocket, we can use the equation:

distance = initial velocity * time + (1/2) * acceleration * time^2

Since the rocket starts from rest (initial velocity = 0), the equation simplifies to:

distance = (1/2) * acceleration * time^2

Substituting the given values, we have:

distance = (1/2) * 35 * 10^2

Simplifying further:

distance = 0.5 * 35 * 100

Calculating the distance:

distance = 1750 meters

To find the final velocity of the rocket, we can use the equation:

final velocity = initial velocity + acceleration * time

Since the rocket starts from rest (initial velocity = 0), the equation simplifies to:

final velocity = acceleration * time

Substituting the given values, we have:

final velocity = 35 * 10

Calculating the final velocity:

final velocity = 350 m/s

Therefore, the rocket will travel a distance of 1750 meters in 10 seconds and its final velocity will be 350 m/s.

Conclusion

The rocket will travel a distance of 1750 meters in 10 seconds and its final velocity will be 350 m/s.