Question

Давление 2 моль идеального газа уменьшилось в 3 раза, а температура уменьшилась в 2 раза .Как изменился обьем? 1)увеличился в 1.5 раза ,2)уменьшилось в 1.5 раза ,3)увеличился в 6 раз ,4)уменьшился в 6 раз

Answer 1

2 уменшилось ы 1.5 раза

Answer 2

Answer:

To determine how the volume of an ideal gas changes when the pressure and temperature change, we can use the combined gas law, which states that the pressure, volume, and temperature of a fixed amount of gas are related. The combined gas law is expressed as:

P1V1 / T1 = P2V2 / T2

Where: - P1 and V1 are the initial pressure and volume, - T1 is the initial temperature, - P2 and V2 are the final pressure and volume, - T2 is the final temperature.

Given that the pressure of 2 moles of an ideal gas decreased by 3 times and the temperature decreased by 2 times, we can calculate the change in volume using the combined gas law.

Using the combined gas law, we can solve for the final volume (V2):

P1V1 / T1 = P2V2 / T2

V2 = (P1V1 * T2) / (P2 * T1)

Now, let's calculate the change in volume based on the given changes in pressure and temperature.

Calculation:

Given: - Initial pressure (P1) = 1 - Initial volume (V1) = 2 - Initial temperature (T1) = 1 - Final pressure (P2) = 1/3 (since the pressure decreased by 3 times) - Final temperature (T2) = 1/2 (since the temperature decreased by 2 times)

Using the formula: V2 = (P1V1 * T2) / (P2 * T1)

V2 = (1 * 2 * 1/2) / (1/3 * 1) V2 = (2 * 1/2) / (1/3) V2 = 1 / (1/3) V2 = 3

So, the final volume (V2) is 3.

Conclusion:

The volume of the ideal gas increased by 1.5 times (from 2 to 3). Therefore, the correct answer is 1) increased by 1.5 times.