Question

Груз массой 1 кг под действием силы 30 Н,направленной вертикально вверх,поднимается на высоту 5 м.Чему равно изменение кинетической энергии груза?

Answer 1

дано: m-1кг,  F-30H ,  h-5м.  q-9.8м/c

A = F · h=30*5=150-сила действия

a=(F-mg)/m=(30-1*9/8)/1=20.2-ускорение груза

t=корень2h/a=корень2*5/20.2=0.70-время подъема

u=at=корень2ah=20.2*0.70=корень2*20.2*5=14.21-скорость в конце подьема

дельтаEk=Ek=m*u^2/2=mah=101, точнее 100.96205 Дж - кинетическая инергия груза, 

 

Answer 2

Calculation of Change in Kinetic Energy

To calculate the change in kinetic energy of the object, we can use the formula:

Change in Kinetic Energy = Work Done

The work done can be calculated using the formula:

Work Done = Force × Distance

Given: - Mass of the object, m = 1 kg - Force acting on the object, F = 30 N - Distance moved by the object, d = 5 m

Using the given values, we can calculate the work done and then determine the change in kinetic energy.

Calculation Steps

1. Work Done - Work Done = Force × Distance - Work Done = 30 N × 5 m - Work Done = 150 J

2. Change in Kinetic Energy - Change in Kinetic Energy = Work Done - Change in Kinetic Energy = 150 J

Therefore, the change in kinetic energy of the object is 150 Joules.

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