Question

СРОЧНА ПАЖАЛУСТА почему равна масса природного газа который нужно сжечь для того, чтобы 4 кг воды нагреть в алюминиeвий кастрюле с массой 0,6 кг от 10 ° С до кипения?

Answer 1

Дано: 
$t_0=10 \ кC \\t=100 \ кC \\ m_1=4 \ _K_\Gamma$
$m_2=0,6 \ _K_\Gamma \ -$ масса алюминиевой кастрюли 
$c_1=4200$ Дж/кг·°С $-$ удельная теплоёмкость воды
$q=44\cdot 10^6$ Дж/кг $-$ удельная теплота сгорания природного газа 
$c_2=920$ Дж/кг·°С $-$ удельная теплоёмкость алюминия 
Найти:
$m_3= \ ?$
Решение: 
Всё тепло сгоревшего топлива - природного газа: 
            $Q_3=q\cdot m_3$ 
Идёт на нагревание воды и алюминиевой кастрюли от 10°С до 100°С:
            $Q_1+Q_2=c_1\cdot m_1\cdot (t-t_0)+c_2\cdot m_2\cdot (t-t_0)$
Получаем что масса сгоревшего природного газа: 
$Q_1+Q_2=Q_3 \\ c_1\cdot m_1\cdot (t-t_0)+c_2\cdot m_2\cdot (t-t_0)=q\cdot m_3$ 
$m_3=\frac{c_1\cdot m_1\cdot (t-t_0)+c_2\cdot m_2\cdot (t-t_0)}{q} = \frac{4200\cdot 4\cdot (100-10)+920\cdot 0,6\cdot (100-10)}{44\cdot 10^6} =0,0356$ кг

Answer 2

Calculation of the Amount of Natural Gas Required to Heat Water in an Aluminum Pot

To determine the amount of natural gas required to heat water in an aluminum pot, we need to consider the specific heat capacity of water, the mass of water, the initial temperature, and the final temperature.

The specific heat capacity of water is approximately 4.18 J/g°C. This means that it takes 4.18 Joules of energy to raise the temperature of 1 gram of water by 1 degree Celsius.

Given the following information: - Mass of water (m1) = 4 kg - Mass of aluminum pot (m2) = 0.6 kg - Initial temperature (T1) = 10°C - Final temperature (T2) = boiling point of water (100°C)

We can calculate the amount of heat energy required to heat the water using the formula:

Q = m1 * c * ΔT

Where: - Q is the heat energy required - m1 is the mass of water - c is the specific heat capacity of water - ΔT is the change in temperature (T2 - T1)

Let's calculate the heat energy required:

Q = 4 kg * 4.18 J/g°C * (100°C - 10°C)

Q = 4 kg * 4.18 J/g°C * 90°C

Q = 1501.2 kJ

Now, we need to determine the amount of natural gas required to produce this amount of heat energy. The energy content of natural gas can vary, but on average, it is around 38.7 megajoules (MJ) per cubic meter (m³) [[1]].

To convert the heat energy from kilojoules (kJ) to megajoules (MJ), we divide by 1000:

Q = 1501.2 kJ / 1000 = 1.5012 MJ

Now, we can calculate the volume of natural gas required:

Volume of natural gas = Q / Energy content of natural gas

Volume of natural gas = 1.5012 MJ / 38.7 MJ/m³

Volume of natural gas ≈ 0.0387 m³

Therefore, approximately 0.0387 cubic meters of natural gas would be required to heat 4 kg of water in an aluminum pot from 10°C to its boiling point.

Please note that the actual amount of natural gas required may vary depending on factors such as the efficiency of the heating system and the specific heat capacity of the aluminum pot.