Question

В чистой воде растворена серная кислота. масса раствора 240 г, а его плотность 1.2г/см^3. определите массу кислоты содержащейся в растворе

Answer 1

M=240 - масса раствора, m₁-масса воды, m₂ - масса кислоты
m₁+m₂=m
m₁=V₁ρ₁
m₂=V₂ρ₂
V₁- объем воды
ρ₁=1 г/см³ - плотность воды
V₂- объем кислоты
ρ₂=1,84 г/см³ - плотность кислоты
отсюда
V₁ρ₁+V₂ρ₂=m
V₂=(m-V₁ρ₁)/ρ₂
с другой стороны
V=V₁+V₂=m/ρ
V₁=m/ρ-V₂

V₂=(m-(m/ρ-V₂)ρ₁)/ρ₂=m/ρ₂-m*ρ₁/(ρ*ρ₂)+V₂ρ₁/ρ₂
V₂(1-ρ₁/ρ₂)=m/ρ₂-m*ρ₁/(ρ*ρ₂)=m(1-ρ₁/ρ)/ρ₂
m₂=V₂ρ₂=m(1-ρ₁/ρ)/(1-ρ₁/ρ₂)=240(1-1/1,2)/(1-1/1,84)=87,62 г

Answer 2

Calculation of the Mass of Sulfuric Acid in the Solution

To determine the mass of sulfuric acid in the solution, we need to use the given information about the mass of the solution and its density.

Given: - Mass of the solution = 240 g - Density of the solution = 1.2 g/cm^3

To find the mass of sulfuric acid, we can use the formula:

Mass = Volume x Density

Since the density is given in grams per cubic centimeter (g/cm^3), we need to convert the volume from grams to cubic centimeters.

To do this, we can use the formula:

Volume = Mass / Density

Let's calculate the volume of the solution first:

Volume = 240 g / 1.2 g/cm^3 = 200 cm^3.

Now that we have the volume of the solution, we can calculate the mass of sulfuric acid using the formula:

Mass of Sulfuric Acid = Volume x Density

Mass of Sulfuric Acid = 200 cm^3 x 1.2 g/cm^3 = 240 g

Therefore, the mass of sulfuric acid contained in the solution is 240 grams.

Please note that the calculation assumes that the density of the sulfuric acid remains constant regardless of its concentration in the solution.